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Mixed AP constraints

Authors
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    Name
    Vu Hung
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Problem Statement

An arithmetic sequence has a3=11a_3=11 and a12=47a_{12}=47. Find a1a_1 and dd, then determine S25S_{25}.


Solutions

Use an=a+(n1)da_n=a+(n-1)d:

a+2d=11,a+11d=47.a+2d=11,\qquad a+11d=47.

Subtract:

9d=36    d=4,9d=36 \implies d=4,

then a=118=3a=11-8=3. Now

a25=3+244=99,a_{25}=3+24\cdot 4=99,

so

S25=252(3+99)=252102=1275.S_{25}=\frac{25}{2}(3+99)=\frac{25}{2}\cdot 102=1275.

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