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Convergence condition

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    Vu Hung
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Problem Statement

Consider the geometric series

n=07(m13)n.\sum_{n=0}^{\infty} 7\left(\frac{m-1}{3}\right)^n.

Find all real values of mm for which the series converges, and then state its sum.


Hints

Use the condition r<1|r|<1 for convergence of an infinite GP.


Solutions

Here

r=m13.r=\frac{m-1}{3}.

Convergence requires

m13<1    m1<3    2<m<4.\left|\frac{m-1}{3}\right|<1 \implies |m-1|<3 \implies -2<m<4.

For these values,

S=71m13=214m.S_\infty=\frac{7}{1-\frac{m-1}{3}}=\frac{21}{4-m}.

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